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9x^2-61x-80=0
a = 9; b = -61; c = -80;
Δ = b2-4ac
Δ = -612-4·9·(-80)
Δ = 6601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-61)-\sqrt{6601}}{2*9}=\frac{61-\sqrt{6601}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-61)+\sqrt{6601}}{2*9}=\frac{61+\sqrt{6601}}{18} $
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